1.A submarine enters a sonar pulse, which returns from an under water cliff in 1.02 s. If the speed of sound in salt water is 1531 m/s, how far away is the cliff? Ans: t = 1.02s, v = 1531m/s Now d=s x t Distance travelled by sonar pulse = 2d = 2x1531x1.02 = 1561.62m Distance of the cliff = d/2= 1561.62/2 = 780.81m 2. If the tension in the wire is increased four times how will the velocity of wave in a string varies? Answer: velocity of the wave in string is directly proportional to the square root of the tension thus if tension is increased 4 times the velocity will be doubled. 3. What is Echo. Explain the conditions that have to be satisfied to hear an echo? Ans: reflection of sound wave from a large obstacle is called an echo. The most important condition for hearing an echo is that the reflected sound should reach the ear only after a lapse of at least 0.1 second after the original sound dies off and the obstacle is at least at a distance of 17 m 4. Why do echoes produced in an ...
CBSE NCERT SOLUTION, STUDY MATERIAL, NOTES,CTET, SAMPLE PAPER, SCIENCE, PHYSICS, CHEMISTRY, BIOLOGY, CBSE QUESTION PAPER, SAMPLE PAPER, CBSE Syllabus; CBSE Model Papers; BOARD Exam PAPER; ONLINE STUDY HELP, STUDY MATERIALS, For CLASS 6 to 12, PDF FILE, YouTube VIDEO for lessons.