CBSE Exam Congruence of Triangle Solved Questions Q. 1. Prove that Sum of Two Sides of a triangle is greater than twice the length of median drawn to third side. Given: Δ ABC in which AD is a median. To prove: AB + AC > 2AD. Construction: Produce AD to E, such that AD = DE. Join EC. Proof: In ΔADB and ΔEDC, AD = DE (Construction) BD = BD (D is the mid point of BC) ∠ ADB = ∠ EDC (Vertically opposite angles) ∴ ΔADB ≅ ΔEDC (SAS congruence criterion) ⇒ AB = ED (CPCT) In ΔAEC, AC + ED > AE ( Sum of any two sides of a triangles is greater than the third side ) ∴ AC + AB > 2AD ( AE = AD + DE = AD + AD = 2AD & ED = AB ) Q. 2. ABC is an isosceles triangle in which AB = AC. Side BA is produced to D such that AD = AB (see the given figure). Show that ∠ BCD is a right angle. In ΔABC, AB = AC
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