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X Class 10 Study Material


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  1. Raul SethiDecember 15, 2012

    thank you sir...very much...
    rahul.sethi

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  2. UnknownJanuary 14, 2013

    thanx this site is very useful

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  3. BeanChronicleSeptember 08, 2013

    Where can I get an English sample paper that is according to the 2013-14 syllabus?

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  4. UnknownSeptember 18, 2013

    easy peasy

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  5. UnknownSeptember 18, 2013

    easy peasy and usfullllllllllllllllll

    ReplyDelete
  6. UnknownSeptember 18, 2013

    very easy and usfullllllllllllllllll

    ReplyDelete
  7. DishaOctober 16, 2013

    thank u.........sir

    ReplyDelete
  8. DishaOctober 16, 2013

    thanks a lot ..........sir

    ReplyDelete
  9. DishaOctober 16, 2013

    thanks a lot.............sir

    ReplyDelete
  10. UnknownDecember 20, 2013

    extremely excellent site....

    ReplyDelete
  11. J.Sunil SirFebruary 18, 2014

    we prepared sample question papers for SA-II class X that help students in preparing for the current year’s exams by way of reviewing and revising the questions available therein.

    ReplyDelete
  12. UnknownApril 01, 2014

    This comment has been removed by a blog administrator.

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  13. Phagu MahatoJune 04, 2014

    Thanks It is really helpful for online learner

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  14. J.Sunil SirAugust 14, 2014

    1. Mrs. Sharma has gone to the jewelers to buy gold jewellery. She asks the jeweler if the jewellery is made of pure gold. The jeweler assure her that it is 10% gold and nothing has been mixed in it. Mrs. Sharma is happy and buys the necklace.
    Read the above passage and answer the following questions:
    (a) Was the jeweler right in saying that the necklace is made of 100% gold?
    (b)What values are promoted by the jeweler?
    (c) What precautions should you take while purchasing gold jewellery?
    (d)Why does Government insist on purchasing Hallmarked jewellery? [Value Based Questions]
    Ans: (a) No, he was wrong. Pure gold is very soft and is therefore not suitable for making jewellery.
    It is alloyed with either silver or copper to make it hard. But sometimes jewelers mix a large quantity of copper and silver in gold to earn more profit.
    (b) Untrustworthiness, cleverness.
    (c) We should always purchase the gold jewellery from a branded shop with proper receipt and Hallmark certificate.
    (d) Government insists on purchasing Hallmarked jewellery as it contains the gold and its alloyed metal (i.e. copper or silver) in a fixed ratio.

    2. Describe with labelled diagram, the Froth Floatation Process used to separate the gangue from a Sulphide ore.
    Ans: Sulphide ore is mixed with water and pine oil. The mixture is agitated (shaken vigorously) with the help of stirrer in the blast of air. Froth is formed, sulphide ore gets attracted towards pine oil in the froth which is skimmed off, dried and concentrated sulphide ore is obtained. Gangue is left behind at the bottom of water.
    3. Give reasons for the following:
    (a)Metals generally do not form compounds with hydrogen.
    (b) A piece of zinc placed in blue copper sulphate solution decolourize it.
    (c) Alumina is dissolve in molten cryolite for electrolysis to obtain aluminium metal.
    Ans:
    (a) Metals are good reducing agents and H2 is weak oxidizing agent therefore, metals do not
    react with hydrogen to form hydrides.
    (b) Zn + CuSO4 ¾¾® ZnSO4 + Cu
    It is due to formation of ZnSO4 (aq) which is colourless.
    (c) It increases electrical conductivity and molten cryolite acts as a solvent.
    4. What is the purpose of the soft iron core used in making an electromagnet?
    Ans: The purpose of soft iron core used in making an electromagnet that:
    (i) It is temporary magnetized.
    (ii) It retains magnetism as long as current flow is maintained.
    (iii) It will ensure an uniform and stronger field.
    5. During the reaction of some metals with dilute hydrochloric acid, following observations were made:
    (i) Silver metal doesn’t show any change.
    (ii) The temperature of reaction mixture rises when aluminium (Al) is added.
    (iii) The reaction of sodium metal is found to be highly explosive.
    (iv) Some bubbles of a gas are seen when lead (Pb) is reacted with the acid.
    (v) A gas produced when sodium carbonate is added to the acid.
    Explain these observations giving suitable reasons.
    Ans: (i) Silver is very less reactive metal. So it does not react with dilute HCl.
    (ii) The reaction of Al with dilute HCl is exothermic i.e. heat is produced in the reaction, so the temperature of the reaction mixture rises.
    (iii) Sodium is a very reactive metal. It react vigorously with the evolution of heat too.
    (iv) Bubbles are seen due to the evolution of H2 gas.
    Pbs + 2HCl ----> PbCl2 + H2
    (v) CO2 gas is produced when Na2CO3 reacts with dilute HCl.
    Na 2CO3 + 2HCl --> 2NaCl + H 2O + CO2

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  15. Hari Prasad ChaudharySeptember 03, 2014

    This comment has been removed by a blog administrator.

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  16. UnknownDecember 09, 2014

    Hello, I love reading through your blog, I wanted to leave a little comment to support you and wish you a good continuation. Wish you best of luck for all your best efforts.

    Brain Development

    ReplyDelete
  17. drishtiJanuary 20, 2015

    Whn an object is placed 20cm from concave mirror a real image magnified 3 times is formed.Find where must the object be placed to give a virtual image 3 times the height of the object? this question is frm reflection of light class 10. plzzz solve it

    ReplyDelete
  18. drishtiJanuary 20, 2015

    whn an object is placed 20cm frm the concave mirror a real image magnified 3 times is formed.Find where must the object be placed to give a virtual image 3 times the height of the object. this question is frm reflection of light class 10. plzzz solve it

    ReplyDelete
  19. drishtiJanuary 20, 2015

    grt blogs!

    ReplyDelete
  20. drishtiJanuary 20, 2015

    grt blogs!

    ReplyDelete
  21. J.Sunil SirJanuary 21, 2015

    (a)
    Magnification, m=-3 (Image is real)
    Object distance, u=-20cm
    Magnification, m=-v/u
    -3=- v/(-20)
    v=-60 cm
    Thus the image is located at a distance of 60cm in front of the mirror.
    Now using the mirror formula,
    1/v +1/u=1/f
    1/(-60) + 1/(-20)=1/f
    f=-15 cm
    (b)
    m=h2 /h1=- v/u=3
    v=-3u
    Using mirror formula,
    1/(-3u) +1/u=1/-15
    u=-10 cm

    ReplyDelete
  22. UnknownMarch 15, 2016

    sir plz provide solution of home based mathematics question paper of year 2016

    ReplyDelete
  23. UnknownJune 13, 2016

    i like this

    ReplyDelete

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CBSE ADDA :By Jsunil Sir : Your Ultimate Destination for CBSE Exam Preparation and Academic Insights

Living science ratna sagar class 6 solutions

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Ratna sagar living science 6 answers by jsunil. Class6 Living science solution Term-1 Living Science Solution chapter-1 Source of food Download File Living Science Solution chapter-2 Component of food Download File Living Science Solution chapter-3 Fibre to fabric Download File Living Science Sol ch-4 Sorting of material into group Download File Living Science Soln ch-5 Separation of substance Download File Living Science Solution chapter-6 Change around Us Download File Living Science Solution ch-7 Living and Non Living Download File Living Science Solution ch-8 Getting to Know Plants Download File Living Science Sol ch-9 The Body and Its movements Download File Visit given link for full answer Class6 Living science solution Term-II
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Class 10 Chapter 02 Acid Bases and Salts NCERT Activity Explanation

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NCERT Activity Chapter 02 Acid Bases and Salt Class 10 Chemistry Activity 2.1 Indicator Acid Base Red litmus No Change Blue Blue Litmus Red No change Phenolphthalein Colourless Pink Methyl Orange Pink   Yellow Indictors are substance which change colour in acidic or basic media. Activity 2.2 There are some substances whose odour changes in in acidic or basic media. These are called olfactory indicators. Like onion vanilla, onion and clove. These changes smell in basic solution. Activity 2.3 Take about 5 mL of dilute sulphuric acid in a test tube and add few pieces of zinc granules to it. => You will observe bubbles of hydrogen gas on the surface of zinc granules. Zn + H2SO4 --> ZnSO4 + H2 => Pass the Hydrogen gas through the soap solution. Bubbles formed in the soap solution as Hydrogen gas it does not get d...
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Class 10 Metal and Non MetalsChapter 03 NCERT Activity Solutions

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X Class 10 NCERT Activity Explanation Class 10 Metals and Non Metals Activity 3.1 Page No. 37 Take samples of iron, copper, aluminium and magnesium. Note the appearance of each sample. They have a shining surface. Clean the surface of each sample by rubbing them with sand paper and note their appearance again. They become more shiny. => Freshly cut Metal have shiny surface Activity 3.2 Page No. 37 Take small pieces of iron, copper, aluminium, and magnesium. Try to cut these metals with a sharp knife and note your observations. They are very hard to cut. Hold a piece of sodium metal with a pair of tongs and try to cut it with a knife. Sodium can be cut easily with knife. Hence K and Na are soft metal cut with knife Activity 3.3 Page No. 38 Take pieces of iron, zinc, lead and copper try to strike it four or five times with a hammer. These metals are beaten into thin sheet on hammering. This property of metal is called malleability and metals are called malleable. Activity 3.4 Page ...
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Class 09 Atoms and Molecules Numerical Problem based on Law of chemical Combination(Solved)

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Class 09 Atoms and Molecules Numerical Problem based on Law of chemical Combination Law of conservation of mass Law of constant proportion Empirical formula 1. If 10 grams of CaCO 3 on heating gave 4.4g of CO 2 and 5.6g of CaO, show that these observations are in agreement with the law of conservation of mass.(Based on Law of conservation of mass) Solution:  Mass of the reactants = 10g ;  Mass of the products = 4.4 + 6.6g = 10g Since the mass of the reactants is equal to the mass of the products, the observations are in agreement with the law of conservation of mass. 2. 1.375 g of cupric oxide was reduced by heating and the weight of copper that remained was 1.098g.  In another experiment 1.179 g of copper was dissolved in nitric acid and the resulting copper nitrate was converted into cupric oxide by ignition . The weight of cupric oxide formed was 1.476 g. which law of chemical combinations does this data state? Solution: in first experiment: Copper oxide = 1....
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CBSE I NCERT 10th Numerical Problem solved Reflection and reflection of light

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Q. 1. A concave mirror of focal length 20cm is placed 50 cm from a wall. How far from the wall an object be placed to form its real image on the wall?  Solution: V= -50 cm F= -20cm From mirror formula 1/u = 1/f – 1/v = -1/20+ 1/50 = - 3/100  U = - 33.3 cm Therefore, the distance of the object from the wall x =  50 – u X = 50 – 33.3 = 16.7 cm. Q.2. An object is placed at a distance of 40cm from a concave mirror of focal length 15cm. If the object is displaced through a distance of 20 cm towards the mirror, By how much distance is the image displaced? Answer: Here f = - 15 cm, u = - 40 cm Now 1/f = 1/u + 1/v Then 1/v = 1/f – 1/u Or V= uf/u-f =( - 40 x -15)/25 = -24 cm Then object is displaced towards the mirror let u1 be the distance object from the Mirror in its new position. Then u1 = -(40-20) = -20cm If the image is formed at a distance u1 from the mirror then v1 = u1f/u1-f = -20X-15/-20+15 = -60 cm. = - 20 x-15/-20+15 = -60 ...
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