CBSE MATH STUDY: 8th maths :8th Linear Equations of one or two Vari...: 8th Mathematics JSUNIL TUTORIAL,SAMASTIPUR What is an equation? A statement which contains the equ...
Class 09 Atoms and Molecules Numerical Problem based on Law of chemical Combination Law of conservation of mass Law of constant proportion Empirical formula 1. If 10 grams of CaCO 3 on heating gave 4.4g of CO 2 and 5.6g of CaO, show that these observations are in agreement with the law of conservation of mass.(Based on Law of conservation of mass) Solution: Mass of the reactants = 10g ; Mass of the products = 4.4 + 6.6g = 10g Since the mass of the reactants is equal to the mass of the products, the observations are in agreement with the law of conservation of mass. 2. 1.375 g of cupric oxide was reduced by heating and the weight of copper that remained was 1.098g. In another experiment 1.179 g of copper was dissolved in nitric acid and the resulting copper nitrate was converted into cupric oxide by ignition . The weight of cupric oxide formed was 1.476 g. which law of chemical combinations does this data state? Solution: in first experiment: Copper oxide = 1....
Very impressive blog about the CBSE 8th class Math syllabus.Generally children takes homework as a burden but it is very essential for them.They need some practice and daily guidance so that they can understand the topic.Teachers has to jut take care of this thing that they should not give it in bulk.And parents also take care of the kids assignments and the strss related to it.
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