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CBSE CLASS 10 Chapter 01: Chemical Reactions and Equations NCERT Activity explanation

X NCERT ACTIVITIES Class 10 Chemical Reactions and Equations Activity 1.1 (Experiment): Activity 1.1 Clean a magnesium ribbon by rubbing it with sandpaper to remove layer of carbonate and oxide. Burn it using a spirit lamp you get white ash of  MgO.            Mg (s) + O 2 (g)      à MgO(s) => Magnesium ribbon burn with dazzling light and white powder of MgO is formed which is basic in nature It is an example of combination reaction in which single compound break into two or more substance. Activity 1.2 (Experiment): Take lead nitrate solution in a test tube. Add potassium iodide solution to this. => Yellow precipitate PbI 2 is formed. Substance Insoluble in water is called precipitate. Pb(NO 3 ) 2   (aq)     +      2KI    à PbI 2 (s) ( ¯ )    +  2 KNO 3   (aq) This is an example of precipitation reaction . This is an example of Double decomposition reaction in which there is exchange of radicals. Activity 1:3 (Experiment): Take a few zinc granules

Class 10 Sample Paper CBSE Board Exam New Pattern

​Class 10 Sample Paper Board Exam 2020-21 10th Science 2020 CBSE Practice Paper -1 Download File 10th Science 2020 CBSE Practice Paper -2 Download File 10th Science 2020 CBSE Practice Paper -3 Download File 10th Science 2020 CBSE Practice Paper -4 Download File 10th Science 2020 CBSE Practice Paper -5 Download File 10th Science 2020 CBSE Practice Paper Solution(1-5) Download File See all sample Papers  Visit

Class 09 Atoms and Molecules Numerical Problem based on Law of chemical Combination(Solved)

Class 09 Atoms and Molecules Numerical Problem based on Law of chemical Combination Law of conservation of mass Law of constant proportion Empirical formula 1. If 10 grams of CaCO 3 on heating gave 4.4g of CO 2 and 5.6g of CaO, show that these observations are in agreement with the law of conservation of mass.(Based on Law of conservation of mass) Solution:  Mass of the reactants = 10g ;  Mass of the products = 4.4 + 6.6g = 10g Since the mass of the reactants is equal to the mass of the products, the observations are in agreement with the law of conservation of mass. 2. 1.375 g of cupric oxide was reduced by heating and the weight of copper that remained was 1.098g.  In another experiment 1.179 g of copper was dissolved in nitric acid and the resulting copper nitrate was converted into cupric oxide by ignition . The weight of cupric oxide formed was 1.476 g. which law of chemical combinations does this data state? Solution: in first experiment: Copper oxide = 1.375g ;   Coppe

Class 08 Science chapter Crop production and management video Lecture

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Class 07 Nutrition In Animals Video lesson by Jsunil SirI Jsunil Tutorial

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Class 07 Chapter Nutrition in Plants video Lesson by Jsunil Sir

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