Biology class IX Ch-07. Diversity in Living Organisms solved Questions New

Diversity in Living Organisms solved CBSE Paper-5

Oswal Question Bank Diversity in Living Organisms Download File

Very Answer type Questions [1 mark each]

1.State the phylum to which centipede and prawn belong. (Board 2013)

Answer: Arthropoda.

2. In which kingdom would you place an organism which is single called, eukaryotic and photo-

synthetic? (Board 2013)

Answer: Protista.

3.Rewrite the scientiﬁc name correctly : (i) panthera tigris (ii) periplaneta Americana. (Board 2012.,

501004)

Answer: (i) Panthers tign's (ii) Periplaneta americana.

4.Name the term which is used for the following

(i) The left and right halves of the body have the same design.

(ii) Animal tissue defferentiate from the three embryonic germ layers. (Board 2012, 501005; 47023)

Answer: (i) Bilaterally symmetrical. (ii) Triploblastic.

5.Name the phylum to which Prawn and Centipede belong. (Board 2012, SC-1008; 47001,)

Answer: Arthropoda.

6. Mention the function and location of notochord.

Answer: Functionn—lt provides a place for muscle to attach for ease of movement.

Location—runs along the back of the animal separating the nervous tissue from the gut.

7. State the phylum to which Antedon (feather star ] and Asterias (Starﬁsh) belong. (Board 2012, 501010)

Answer: Echinodermata.

8.Mention any one characteristic feature of saprophytes. (Board 2012, 47005)

Answer: They have cell wall made of tough compare sugars called chitin.

9.Which in your opinion is more basic characteristics for classifying organism - the place where they live in or the kind of cells they are made of ? (Board 2012, 501006)

Answer: The kind of cells the organisms are made of.

10. Write the name of phylum to which Hydra and Sea anemone belong.- (Board 2012, 47017)

Answer: Coelenterata.

11. Name the phylum to which Leech and Earthworm belong. (Board 2012, 47004 }

Answer: Annelida.

12. Name a division of plants which can be classiﬁed as cryptogarnae. (Board 2012, 47010}

Answer: Pteridophyta / Thallophyta / Bryophyta. (Any one)

13. State the system in poriferans that heips in circulating water throughout the body to bring in food and oxygen. (Board 2012, SC-1011}

Answer: Canal System

14. Write an example of the species which belong to this phylum and lives in colonies.

Answer: Corals.

15. Name the phylum to which Octopus and Unio belong ? (Board 2012, 4700}

Answer: Mollusca.

Diversity in Living Organisms solved CBSE Paper-1

Diversity in Living Organisms solved CBSE Paper-2
Diversity in Living Organisms solved CBSE Paper-3
Diversity in Living Organisms solved CBSE Paper-4
Diversity in Living Organisms NCERT Solution
9th Diversity in Living Organisms Study Notes
9th 9th Diversity in Living World Notes Download File

Comments

CBSE ADDA :By Jsunil Sir : Your Ultimate Destination for CBSE Exam Preparation and Academic Insights

Class 10 Chapter 02 Acid Bases and Salts NCERT Activity Explanation

NCERT Activity Chapter 02 Acid Bases and Salt Class 10 Chemistry Activity 2.1 Indicator Acid Base Red litmus No Change Blue Blue Litmus Red No change Phenolphthalein Colourless Pink Methyl Orange Pink Yellow Indictors are substance which change colour in acidic or basic media. Activity 2.2 There are some substances whose odour changes in in acidic or basic media. These are called olfactory indicators. Like onion vanilla, onion and clove. These changes smell in basic solution. Activity 2.3 Take about 5 mL of dilute sulphuric acid in a test tube and add few pieces of zinc granules to it. => You will observe bubbles of hydrogen gas on the surface of zinc granules. Zn + H2SO4 --> ZnSO4 + H2 => Pass the Hydrogen gas through the soap solution. Bubbles formed in the soap solution as Hydrogen gas it does not get d...

CBSE I NCERT 10th Numerical Problem solved Reflection and reflection of light

Q. 1. A concave mirror of focal length 20cm is placed 50 cm from a wall. How far from the wall an object be placed to form its real image on the wall? Solution: V= -50 cm F= -20cm From mirror formula 1/u = 1/f – 1/v = -1/20+ 1/50 = - 3/100 U = - 33.3 cm Therefore, the distance of the object from the wall x = 50 – u X = 50 – 33.3 = 16.7 cm. Q.2. An object is placed at a distance of 40cm from a concave mirror of focal length 15cm. If the object is displaced through a distance of 20 cm towards the mirror, By how much distance is the image displaced? Answer: Here f = - 15 cm, u = - 40 cm Now 1/f = 1/u + 1/v Then 1/v = 1/f – 1/u Or V= uf/u-f =( - 40 x -15)/25 = -24 cm Then object is displaced towards the mirror let u1 be the distance object from the Mirror in its new position. Then u1 = -(40-20) = -20cm If the image is formed at a distance u1 from the mirror then v1 = u1f/u1-f = -20X-15/-20+15 = -60 cm. = - 20 x-15/-20+15 = -60 ...

Class 10 Metal and Non MetalsChapter 03 NCERT Activity Solutions

X Class 10 NCERT Activity Explanation Class 10 Metals and Non Metals Activity 3.1 Page No. 37 Take samples of iron, copper, aluminium and magnesium. Note the appearance of each sample. They have a shining surface. Clean the surface of each sample by rubbing them with sand paper and note their appearance again. They become more shiny. => Freshly cut Metal have shiny surface Activity 3.2 Page No. 37 Take small pieces of iron, copper, aluminium, and magnesium. Try to cut these metals with a sharp knife and note your observations. They are very hard to cut. Hold a piece of sodium metal with a pair of tongs and try to cut it with a knife. Sodium can be cut easily with knife. Hence K and Na are soft metal cut with knife Activity 3.3 Page No. 38 Take pieces of iron, zinc, lead and copper try to strike it four or five times with a hammer. These metals are beaten into thin sheet on hammering. This property of metal is called malleability and metals are called malleable. Activity 3.4 Page ...

Living science ratna sagar class 6 solutions

Ratna sagar living science 6 answers by jsunil. Class6 Living science solution Term-1 Living Science Solution chapter-1 Source of food Download File Living Science Solution chapter-2 Component of food Download File Living Science Solution chapter-3 Fibre to fabric Download File Living Science Sol ch-4 Sorting of material into group Download File Living Science Soln ch-5 Separation of substance Download File Living Science Solution chapter-6 Change around Us Download File Living Science Solution ch-7 Living and Non Living Download File Living Science Solution ch-8 Getting to Know Plants Download File Living Science Sol ch-9 The Body and Its movements Download File Visit given link for full answer Class6 Living science solution Term-II

Electricity numerical for class 10 CBSE Trend Setter 50 Problems

1. The current passing through a room heater has been halved. What will happen to the heat produced by it? 2. An electric iron of resistance 20 ohm draws a current of 5 amperes. Calculate the heat produced in 30 seconds. 3. An electric heater of resistance 8 ohm takes a current of 15 A from the mains supply line. Calculate the rate at which heat is developed in the heater. 4. A resistance of 40 ohms and one of 60 ohms are arranged in series across 220 volt supply. Find the heat in joules produced by this combination in half a minute. 5. A resistance of 25 ohm is connected to a 12 V battery. Calculate the heat energy in joules generated per minute. 6. 100 joules of heat is produced per second in a 4 ohm resistor. What is the potential difference across the resistor? 7. An electric iron is connected to the mains power supply of 220 V. When the electric iron is adjusted at minimum heating’ it consumes a power of 360 W but at ‘maximum heating’ it takes a power of 840 W. Ca...

CBSE ADDA

Search This Blog