|
Dear
Professionals
|
||||||||||||
|
UGC NET Solved Paper
I, II, III
|
||||||||||||
|
available on http://www.netugc.com/
|
||||||||||||
|
UGC NET Paper I: Solved
|
||||||||||||
|
§ UGC NET Paper II: Solved
|
||||||||||||
|
UGC NET Paper III: Solved
|
||||||||||||
| ||||||||||||
Class 09 Atoms and Molecules Numerical Problem based on Law of chemical Combination Law of conservation of mass Law of constant proportion Empirical formula 1. If 10 grams of CaCO 3 on heating gave 4.4g of CO 2 and 5.6g of CaO, show that these observations are in agreement with the law of conservation of mass.(Based on Law of conservation of mass) Solution: Mass of the reactants = 10g ; Mass of the products = 4.4 + 6.6g = 10g Since the mass of the reactants is equal to the mass of the products, the observations are in agreement with the law of conservation of mass. 2. 1.375 g of cupric oxide was reduced by heating and the weight of copper that remained was 1.098g. In another experiment 1.179 g of copper was dissolved in nitric acid and the resulting copper nitrate was converted into cupric oxide by ignition . The weight of cupric oxide formed was 1.476 g. which law of chemical combinations does this data state? Solution: in first experiment: Copper oxide = 1....

Comments
Post a Comment