C.B.S.E.2012-Sample-Papers For SA-1 IX-Physics: Chemistry : Biology : Mathematics |
C.B.S.E.-2012-Sample-Papers-for-IX-Physics-(5-Sets)-Summative-Assessement-I |
C.B.S.E.-2012-Sample-Papers-for-IX-Chemistry-(5-Sets)-Summative-Assessement-I |
C.B.S.E.-2012-Sample-Papers-for-IX-Biology-(5-Sets)-Summative-Assessement-I |
C.B.S.E.-2012-Sample-Papers-for-IX-Science Set-1 -Summative-Assessment-I |
C.B.S.E.-2012-Sample-Papers-for-IX-Science Set-2 -Summative-Assessment-I |
C.B.S.E.-2012-Sample-Papers-for-IX-Science Set-3 -Summative-Assessment-I |
C.B.S.E.-2012-Sample-Papers-for-IX-Mathematics Set-1 -Summative-Assessment-I |
C.B.S.E.-2012-Sample-Papers-for-IX-Mathematics Set-2 -Summative-Assessment-I |
C.B.S.E.-2012-Sample-Papers-for-IX-Mathematics Set-3 -Summative-Assessment-I |
Class 09 Atoms and Molecules Numerical Problem based on Law of chemical Combination Law of conservation of mass Law of constant proportion Empirical formula 1. If 10 grams of CaCO 3 on heating gave 4.4g of CO 2 and 5.6g of CaO, show that these observations are in agreement with the law of conservation of mass.(Based on Law of conservation of mass) Solution: Mass of the reactants = 10g ; Mass of the products = 4.4 + 6.6g = 10g Since the mass of the reactants is equal to the mass of the products, the observations are in agreement with the law of conservation of mass. 2. 1.375 g of cupric oxide was reduced by heating and the weight of copper that remained was 1.098g. In another experiment 1.179 g of copper was dissolved in nitric acid and the resulting copper nitrate was converted into cupric oxide by ignition . The weight of cupric oxide formed was 1.476 g. which law of chemical combinations does this data state? Solution: in first experiment: Copper oxide = 1....
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