Skip to main content

CBSE SAMPLE PAPER 8TH MATHEMATICS SA-1

8th Maths Sample paper for  Practice 

1. What least number must be subtracted from 7250 to get a perfect square? Also, find the square root of this perfect square

2. What is the least number by which 12348must be divided to obtain a perfect square?

3. Find the cost of erecting a fence around a square field whose area is 9 hectares if fencing costs Rs 3.50 per metre

4. Find the least number of six digits which is a perfect square. Find the square root of this number.

5. Divide
(1) x3 - 1 by x - 1 (2) 7 +15x -13x2 +5x3 by 4 - 3x + x2

6. . x + y + z = 0, prove that x 3+ y3 + z3 = 3xyz. Or, Factorize : (a8 – b8)

7. If ( x2 + 1/X2) = 83 . Find X3- 1/X3

Or, , Factorize (i) 25a² – 4b² + 28bc – 49c² (ii) 5y² – 20y – 8z + 2yz

8. A motor boat covers a certain distance downstream in a river in 5 hours. It covers the same distance upstream in 6 hours. The speed of water is 2 km/hr . Find the speed of the boat in still water.

9. Three prizes are to be distributed in a quiz contest. The value of the second prize is five sixths the value of the first prize and the value of the third prize is four – fifths that of the second prize. If the total value of three prizes is Rs. 150, find the value of each prize.

10. (a) Each side of a triangle is increased by 10 cm. If the ratio of the perimeters of the new triangle and the given triangle is 5 : 4, find the perimeter of the given triangle

(b) . The difference between two positive integers is 36. The quotient, when one integer is divided by the other is 4. Find the two integers.

11. Factorize

(1) x4 – (y + z)4 (2) y2 –7y +12 (3) 6xy – 4y + 6 – 9x  (4) a4 – 2a²b² + b4 (5) (x² – 2xy + y²) – z² 

8th Factorization

1. Factorization

(1) (a + b ) (1 – c ) – (b + c ) ( 1 – c ) (2) 1 6 a2 + 40 a b + 25 b2 (3) 4x2/9 - 2/3 x y + y2 /4

(4) 5x2yz - 5 x3y (5) 18 q2 + 338 p2 - 1 5 6 p q (6) -108 x2 - 363 y2 + 369 x y

2. Factorize

(1) 16- 4x2 (2) 20 x3 – 45 b4x (3) 4a2 – 9 b2 – c2 - 6bc

4) 25 ( x + 2y )2 - 36 (2x-5y)2 (5) a2 + 2 a b + b2 – c2 -2cd –d2

3. Factorize using a2+b2+c2 +2ab+2bc+2ca

(1) x2 + y2 + 25 z2 – 2 x y – 10 y z + 10 z x (2) 9x2 + 4y2 + 49z2 – 12 x y + 28 y z – 42 z x

(3) 4x6 + 9y6 + 16 x 6 + 12 x3 y3 + 16 x3 z3 + 24 y3z3 (4) a8 + 256 b8 + 96 a4b4-16a3b2 – 256a2b6

4. Factorize (x + a) (x + b) = x2 + (a + b) x +a b

(1) x2+7x+ 10 (2) x2+x-20 (3) x2-4x-21 (4) 15x2 + 13x + 2 (5) -6x2 - 13x+5

5. Factorize

(1) 125 a3 + 150 a2b + 60 ab3 + 8ab3 (2) x6 – 12 x4 b4 c + 6a2b5c2 + b6c3 (3) 81a3 + 24b3

(4) 64a3b2 – 125 b5 (5) 16 a3 – 54 b3 (6) 8X + 1

(7) a3 - 27b3 (8) 729a6 - 1 (9) 8m3 + 64 (10) 1000 – 343 a9

6. Find the following products:

(1) (9m + 2m )( 81m2 -18mn + 4n2) (2) (5 - 2x ) (25 +10x + 4x2) (3) (3 + 5/x ) ( 9 – 15/x + 25/x2)

7. Find the value of 27x2 + 64y2 + 36xy(3x + 4y) , when x = 5 and y = -3.

8. Using the identity (x + a) (x + b) = x2 + (a + b)x + a b, evaluate 98 x 97

9. x + y + z = 0, prove that x 3+ y3 + z3 = 3xyz.

10. Factorize

(1) m4 – 256 (2) y2 –7y +12 (3) 6xy – 4y + 6 – 9x

(4) x4 – (y + z)4 (5) a4 – 2a²b² + b4 (6) (l + m) ² – 4lm

(7) (x² – 2xy + y²) – z² (8) 25a² – 4b² + 28bc – 49c² (9) 5y² – 20y – 8z + 2yz

(10) a8 – b8

8th Linear Equations In One and two Variable

1. The perimeter of a rectangular swimming pool is 154 metres. Its length is 2m more than twice its breadth. What are the length and breadth of the pool.

2. Sum of two numbers is 95. If one exceeds the other by 15 find the numbers.

3. Two numbers are in the ration 5:3. If they differ by 18, find these numbers

4. Three consecutive integers add up to 51. What are these integers?

5. The sum of three consecutive multiples of 8 is 888. Find the multiple.

6. Three consecutive integers are as such when they are taken in increasing order and multiplied by 2, 3, and 4 respectively, they add up to 74. Find these numbers.

7. The number of boys and girls in a class is in 7:5 ratio. The number of boys is 8 more than that of girls. Fin their numbers.

8. The ages of Rahul and Haroon are in the ratio of 5:7. Four years from now sum of their ages will be 56 years. Find their present age.

9. Baichung’s father is 26 years younger than Baichung’s grandfather and 29 years older than Baichung. The sum of their ages is 135. Find their ages.

10. Fifteen years from now Ravi’s age will be 4 times his current age. What is his current age.

11. Lakshmi is a cashier in a bank. She has notes of denominations of Rs. 100, 50 and 10 respectively. The ratio of number of these notes is 2:3:5 respectively. The total cash with Lakshmi is 4,00,000. How many notes of each denomination does she have?

12. I have total Rs 300 in coins of denominations of Rs.1, Rs.2, and Rs. 5.The number of Rs. 2 coins is 3 times the number of Rs. 5 coins. The total number of coins is 160. How many coins of each denomination are with me.

13. The organizers in an essay competition decide that winner will get a prize of Rs. 100 and a participation who doesn’t win gets a prize of Rs. 25. The total prize money distributed is Rs. 3,000. Find the number of winners if the total number of participants is 63.

14. If in a rational number denominator is greater than numerator by 8. If you increase the numerator by 17 and decrease the denominator by 1, you get 3/2 as result. Find the number.

15. Amina thinks of a number and subtracts 5/2 from it. She multiplies the result by 8. The final result is 3 times her original number. Find the number

16. A positive number is 5 times another number. If 21 is added to both the numbers then one of the new numbers becomes twice of another new numbers. Find the original numbers.

17. Sum of the digits of a two digit number is 9. When we interchange the digits the new number is 27 greater than the earlier number. Find the number.

18. One of the digits of a two digit number is three times the other digit. If you interchange the digits and add the resulting number to original number you get 88 as final result. Find the numbers.

19. Sahoo’s mother’s present age is six times Sahoo’s present age. Five year from now Sahoo’s age will be one-third of his mother’s age. Find their current age.

20. There is a narrow rectangular plot. The length and breadth of the plot are in the ratio of 11:4. At the rate of Rs. 100 per metre it will cost village panchayat Rs.75000 to fence the plot. What are the dimensions of the plot.

21. Hasan buys two kinds of cloth materials for school uniform. Shirt material cost him Rs. 50 per metre and trousers material cost him Rs. 90 per metre. For every 2 metres of the trousers material he buys 3 metres of shirt material. He sells them at 12% and 10% profit respectively. His total sale is Rs. 36,660. How much trousers material did he buy? ( 200m)

22. Half of a herd of deer are grazing in the field and three fourths of the remaining are playing nearby. The rest 9 are drinking water from the pond. Find the total number of deer in the herd.

23. A grandfather is 10 times older than his granddaughter. He is also 54 years older than her. Find their age.

24. A man’s age is three times his son’s age. Ten years ago his age was five times his son’s age. Find their current age.

25. Hari and Harry’s age are in the ratio of 5:7. Four years later the ratio of their ages will be 3:4. Find their current age.

8th Algebraic Expression

1. If ( x + 1 / x ) = 4, Find the value of ( x2 + 1/x2 ) and (x4 + 1/x4 )

2. If ( x - 1/ x ) = 3 .Find the value of (x3 + 1/x3 )

3. Find the remainder obtained by dividing x3 + 3 x2 - 5x + 4 by x + 1

4. Evaluate using algebraic identities (54)2 ; (78)2; (999)2

5. If x - y = 7, x y = 9 Find the value of x2 + y2

6. If x + y = 12 , x y = 27 Find the value of x3 + y3

7. If a2 + b2 + c2 =20 , a + b + c = 6 find a b + b c + ca

8. If ( x2 + 1 / x2 ) = 83 . Find (x3 - 1 / x3 )

9. What must be subtracted from 4p2 - 2pq - 6q2 - r +5 to get - p2 + p q - 8q2 - 2r+5

10. Factorise a3 + b3 + c3 - 3 a b c

11. Devide

(1) x3 - 1 by x - 1

(2) 7 +15x -13x2 +5x3 by 4 - 3x + x2

12. Evaluate

(1) 1.5 3 - 0.93 - 0.63

(2) (a - b) 3 + (a + b) 3

(3) (x + 2y -3z)2 + (x - 2y +3z)2

13.If (x4 + 1 / x4 ) = 47 find the value of (x3 + 1 / x3 )

14. Find the product of

(1) (x4 + 1/x4 ) and ( x + 1/x )

(2) (2x2 + 3x - 7)(3x2 -5x - 4)

15.Two adjacent side of a rectangle are 5x2-3y2 and x2 - 2xy Find its perimeter

16.The perimeter of a triangle is 6p2 - 4p + 9 and two of its adjacent side are

p2 - 2p + 1 and 3 p2 - 5p + 3. Find third side of triangle.

17. Find the least no. of 5 digits which is perfect square.

18. Find the greatest num. of 6 digits which is perfect square.

19. Evaluate

(1) (5-1 x 3-1 )-1 x 6-1 (2) ( 23x+1 +10 ) / 7 = 6

(3) [52x+1]/ 25 = 125 (4) (4/9)4 x (4/9) - 7 = (4/9) 2x – 1
Compound Interest:


1.       You invest Rs 5000 at 12% interest compounded annually. How much is in the account after 2 years, assuming that you make no subsequent withdrawal or deposit? 
2.       Find the amount and the compound interest on Rs 4000 at 10% p.a. for 2½ years. 
3.       A man invests Rs 5000 for three years at a certain rate of interest, compounded annually. At the end of one year it amounts to Rs 5600. Calculate (i) the rate of interest per annum, (ii) the interest accrued in the second year, (iii) the amount at the end of the third year. 
4.       sum of Rs 9600 is invested for 3 years at 10% per annum at compound interest. (i) What is the sum due at the end of the first year? (ii) What is the sum due at the end of the second year? (iii) Find the compound interest earned in two years. (iv) Find the difference between the answers (ii) and (i) and find the interest on this sum for one year. (v) Hence write down the compound interest for the third year. 
5.       Find the difference between the S.I. and C.I. on Rs 2500 for 2 years at 4% p.a., compound interest reckoned semi-annually. 
6.       Find the amount and the compound interest on Rs 8000 in 2 years if the rate is 10% for the first year and 12% for the second year. 
7.       A man invests Rs 6500 for 3 years at 4·5% p.a. compound interest reckoned yearly. Income tax at the rate of 20% is deducted at the end of each year. Find the amount at the end of the third year. 
8.       Calculate the compound interest for the second year on Rs 8000 invested for 3 years at 10% p.a. 
9.       Find the sum which amounts to Rs 9261 at 10% p.a. compound interest for 18 months, interest payable half-yearly. 
10.   On what sum will the compound interest for 2 years at 5% p.a. be Rs 246? 
11.   On what sum will the compound interest (reckoned yearly) for 3 years at 6¼% per annum be Rs 408·50?  
12.   A man invests Rs 1200 for two years at compound interest. After one year his money amounts to Rs 1275. Find the rate of compound interest. Also find the amount which the man will get after 2 years correct to the nearest paise. 
13.   At what rate percent per annum compound interest will Rs 2000 amount to Rs 2315·25 in 3 years? 
14.   If Rs 50000 amounts to Rs 73205 in 4 years, find the rate of compound interest payable yearly. 
15.   In what time will Rs 15625 amount to Rs 17576 at 4% per annum compound interest? 
16.   In what time will a sum of Rs 2500 produce Rs 309 at 6% per annum compound interest? 
17.   In what time will a sum of Rs 800 at 10% per annum compounded half-yearly produce Rs 126·10? 
18.   The simple interest on a sum of money for 2 years at 4% p.a. is Rs 450. Find the compound interest on this sum of money at the same rate (i) for 1 year if the interest is reckoned semi-annually. (ii) for 2 years if the interest is reckoned annually. 
19.   At what rate of compound interest will Rs 625 amount to Rs 729 after 2 years? Also find the maturity value of Rs 625 after 2 years at the above rate of simple interest. 
20.   Ram and Bhola each borrow equal sums for 3 years at 10% p.a. simple interest and compound interest respectively. At the time of repayment, Bhola has to pay Rs 372 more than Ram. Find the sum borrowed and interest paid by each. 
21.   The difference between the compound interest for a year payable half-yearly and the simple interest on a certain sum of money lent out at 10% p.a. for a year is Rs 15. Find the sum of money lent out. 
22.   The difference between compound interest and simple interest in 3 years at 10% p.a. reckoned yearly is Rs 18·60. Find the sum and the compound interest. 
23.   The amount at compound interest which is calculated yearly on a certain sum of money is Rs 1250 in one year and Rs 1375 in two years. Calculate the rate of interest. 
24.   A certain sum of money amounts to Rs 10584 in two years and to Rs 11113·20 in three years, interest being compounded annually. Find the interest rate percent and the original sum. 
25.   The compound interest and the simple interest on the same sum of money at the same rate percent per annum are Rs 410 and Rs 400 respectively. Find the rate of interest and the sum of money. 
26.   The compound interest calculated yearly on a certain sum of money for the second year is Rs 880 and for the third year it is Rs 968. Find the rate of interest and the original money. 
27.   The simple interest on a certain sum for 3 years is Rs 150 and the compound interest on the same sum at the same rate for 2 years is Rs 110. Find the rate of interest and the principal. 
28.   A sum of money lent at C.I. on 1st April 96 amounts to Rs 2420 on 1st April 98 and to Rs 2662 on 1st April 99. Find the rate of interest and the sum. 
29.   The simple interest in 3 years and the compound interest in 2 years on a certain sum at the same rate are Rs 1200 and Rs 832 respectively. Find (i) the rate of interest, (ii) the principal, (iii) the difference between C.I. and S.I. for three years. 
30.   The value of a machine depreciates every year at the rate of 10% of its value. The machine was purchased for Rs 40000 when new and it was sold for Rs 29160. Find the number of years that the machine was used. 
31.   A man borrowed a sum of money and agrees to pay off by paying Rs 3150 at the end of the first year and Rs 4410 at the end of the second year. If the rate of compound interest is 5% p.a., find the sum borrowed. 
32.   A man borrowed a certain sum of money and paid it back in 2 years in two equal instalments. If the rate of compound interest was 4% p.a. and if he paid Rs 676 annually, what sum did he borrow? 
33.   A sum of Rs 16400 is borrowed to be paid back in 2 years by two equal annual instalments allowing 5% compound interest. Find the annual payment. 
34.   A loan of Rs 4641 is to be paid back by 4 equal annual instalments. The interest is compounded yearly at 10%. Find the value of each instalment. 

35.   A man borrows Rs 6000 at 5% p.a. compound interest. If he repays Rs 1200 at the end of each year, find the amount outstanding at the beginning of the third year.
Answers
1. Rs 6272      2. Rs 5082; Rs 1082   3. (i) 12% (ii) Rs 672 (iii) Rs 6952·64
4. (i) Rs 10560 (ii) Rs 11616 (iii) Rs 2016  (iv) Rs 1056, Rs 105·60 (v) Rs 1161·60
5. Rs 6·08         6. Rs 9856; Rs 1856           7. Rs 7227·56
8. Rs 880       9. Rs 8000         10. Rs 2400       11. Rs 2048
12. 6¼%; Rs 1354·69             13. 5%           14. 10%
15. 3 years       16. 2 years                  1 7. 1½ years
18. (i) Rs 227·25 (ii) Rs 459         19. 8%; Rs 725 20. Rs 12000; Rs 3600, Rs 3972
21. Rs 6000 22. Rs 600; Rs 196·60 23. 10%     24. 5% p.a., Rs 9600 25. 5% p.a., Rs 4000
26. 10%, Rs 8000 27. 20%; Rs 250   28. 10%, Rs 2000  29. (i) 8% (ii) Rs 5000 (iii) Rs 98·56
30. 3 years 31. Rs 7000 32. Rs 1275  33. Rs 8820 34. Rs 1464·10 35. Rs 4155

Comments

Post a Comment

CBSE ADDA :By Jsunil Sir : Your Ultimate Destination for CBSE Exam Preparation and Academic Insights

Class 10 Chapter 02 Acid Bases and Salts NCERT Activity Explanation

NCERT Activity Chapter 02 Acid Bases and Salt Class 10 Chemistry Activity 2.1 Indicator Acid Base Red litmus No Change Blue Blue Litmus Red No change Phenolphthalein Colourless Pink Methyl Orange Pink   Yellow Indictors are substance which change colour in acidic or basic media. Activity 2.2 There are some substances whose odour changes in in acidic or basic media. These are called olfactory indicators. Like onion vanilla, onion and clove. These changes smell in basic solution. Activity 2.3 Take about 5 mL of dilute sulphuric acid in a test tube and add few pieces of zinc granules to it. => You will observe bubbles of hydrogen gas on the surface of zinc granules. Zn + H2SO4 --> ZnSO4 + H2 => Pass the Hydrogen gas through the soap solution. Bubbles formed in the soap solution as Hydrogen gas it does not get dissolved in it

CBSE I NCERT 10th Numerical Problem solved Reflection and reflection of light

Q. 1. A concave mirror of focal length 20cm is placed 50 cm from a wall. How far from the wall an object be placed to form its real image on the wall?  Solution: V= -50 cm F= -20cm From mirror formula 1/u = 1/f – 1/v = -1/20+ 1/50 = - 3/100  U = - 33.3 cm Therefore, the distance of the object from the wall x =  50 – u X = 50 – 33.3 = 16.7 cm. Q.2. An object is placed at a distance of 40cm from a concave mirror of focal length 15cm. If the object is displaced through a distance of 20 cm towards the mirror, By how much distance is the image displaced? Answer: Here f = - 15 cm, u = - 40 cm Now 1/f = 1/u + 1/v Then 1/v = 1/f – 1/u Or V= uf/u-f =( - 40 x -15)/25 = -24 cm Then object is displaced towards the mirror let u1 be the distance object from the Mirror in its new position. Then u1 = -(40-20) = -20cm If the image is formed at a distance u1 from the mirror then v1 = u1f/u1-f = -20X-15/-20+15 = -60 cm. = - 20 x-15/-20+15 = -60 cm. Therefor

Class 10 Metal and Non MetalsChapter 03 NCERT Activity Solutions

X Class 10 NCERT Activity Explanation Class 10 Metals and Non Metals Activity 3.1 Page No. 37 Take samples of iron, copper, aluminium and magnesium. Note the appearance of each sample. They have a shining surface. Clean the surface of each sample by rubbing them with sand paper and note their appearance again. They become more shiny. => Freshly cut Metal have shiny surface Activity 3.2 Page No. 37 Take small pieces of iron, copper, aluminium, and magnesium. Try to cut these metals with a sharp knife and note your observations. They are very hard to cut. Hold a piece of sodium metal with a pair of tongs and try to cut it with a knife. Sodium can be cut easily with knife. Hence K and Na are soft metal cut with knife Activity 3.3 Page No. 38 Take pieces of iron, zinc, lead and copper try to strike it four or five times with a hammer. These metals are beaten into thin sheet on hammering. This property of metal is called malleability and metals are called malleable. Activity 3.4 Page

Living science ratna sagar class 6 solutions

Ratna sagar living science 6 answers by jsunil. Class6 Living science solution Term-1 Living Science Solution chapter-1 Source of food Download File Living Science Solution chapter-2 Component of food Download File Living Science Solution chapter-3 Fibre to fabric Download File Living Science Sol ch-4 Sorting of material into group Download File Living Science Soln ch-5 Separation of substance Download File Living Science Solution chapter-6 Change around Us Download File Living Science Solution ch-7 Living and Non Living Download File Living Science Solution ch-8 Getting to Know Plants Download File Living Science Sol ch-9 The Body and Its movements Download File Visit given link for full answer Class6 Living science solution Term-II

Electricity numerical for class 10 CBSE Trend Setter 50 Problems

1. The current passing through a room heater has been halved. What will happen to the heat produced by it? 2. An electric iron of resistance 20 ohm draws a current of 5 amperes. Calculate the heat produced in 30 seconds. 3. An electric heater of resistance 8 ohm takes a current of 15 A from the mains supply line. Calculate the rate at which heat is developed in the heater. 4. A resistance of 40 ohms and one of 60 ohms are arranged in series across 220 volt supply. Find the heat in joules produced by this combination in half a minute. 5. A resistance of 25 ohm is connected to a 12 V battery. Calculate the heat energy in joules generated per minute. 6. 100 joules of heat is produced per second in a 4 ohm resistor. What is the potential difference across the resistor? 7. An electric iron is connected to the mains power supply of 220 V. When the electric iron is adjusted at minimum heating’ it consumes a power of 360 W but at ‘maximum heating’ it takes a power of 840 W. Ca