**Trigonometric Ratios of 30**

^{0}

**and 60**

^{0}

^{}

^{ }

AD ^ BC, then D bisects the side BC. So, BD = DC= a/2

and < BAD = < DAC = 30

^{0}.Now, in right triangle ADB, < BAD = 30

^{0}and BD= a/2So, AB

^{2}= AD^{2 }+ BD^{2 }a

^{2 }= AD^{2 }+ (a/2)^{2}AD = √3/2 a

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