Skip to main content

Edugain HOTS Questions with Answer CBSE Chapter Magnetic Effects of Electric Currents

HOTS Questions with Answer:  Magnetic Effects of Electric Currents

Q1.On what factors does the magnetic field intensity at the centre of the circular coil carrying current  depend ?
Answer: The magnetic field intensity at the centre of the circular coil is directly proportional to current and inversely proportional to radius of the coil. So, in both the cases ,that is, twice the current as well as half in radius, the magnetic field intensity gets doubled.

The magnitude of the magnetic field (B) at the of the coil is:
(i). directly proportional to the current (I) flowing it.
      i.e.   B α I                           ①
(ii). Inversely proportional to the radius (r) of the coil
    i.e.  B α 1/r                              ②
From ①, and , we get

             B α I/r

Q2.State the principle used to determine the force experienced by a conductor carrying current in uniform magnetic field ?

Answer: .Fleming’s Left Hand Rule-Stretch the first three fingers of the left hand mutually perpendicular to each other such that the fore finger points in the direction of magnetic field, the middle finger points in the direction of current, then the thumb will indicate the direction of force experienced by the conductor.
Q3.On what factors does the force experienced by a conductor carrying current in uniform magnetic field depend?
Answer: .Force experienced by a conductor depends on
(a)Current and
(b)The perpendicular distance between that point and the conductor.
(c)Magnetic field strength

Q4.On what factors does the strength of a magnetic field at a point due to a straight conductor carrying current depend ?
Answer:.(a)Magnitude of electric current and
(b)perpendicular distance between that point and the . Conductor.
The magnitude of the magnetic field (B) at the of the coil is:
(i). directly proportional to the current (I) flowing it.
      i.e.   B α I                           ①
(ii). Inversely proportional to the radius (r) of the coil
    i.e.  B α 1/r                              ②
(iii). directly proportional to total number of turns (N) in the coil.
           i.e. B α N                              ③
From ①, ② and ③, we get

             B α I x N/r

Q5.Differentiate between direct current and alternating current.
Answer:
Direct current
In direct current
 (a)It has constant
a) It varies in magnitude.
(b)It has constant
b) It changes its direction alternatively
(c)It is less dangerous in terms of terms of shock.
c) It is more dangerous in eclectic shock.

Q6.A switch is always connected in
(a)earth wire         (b)neutral wire                   (c)live wire

Answer: . It is always connected with live wire.

Q7.What type of connection is used in household circuits?
Answer: .In household circuits all electrical appliances are connected in parallel.

Q8.State the principle of the working of an electric motor.
Answer: .An electric motor works on the principle of force experienced by a current carrying conductor in a magnetic field. The two forces acting are equal and opposite. Since they act in different lines the bring rotational motion.

Q9.State the principle of a D.C generator.
Answer: .It is based on the principle of electromagnetic induction.

Q10.State the characteristics of magnetic field lines.
Answer:
Magnetic field
 The space surrounding a magnet in which magnetic force is exerted is called a magnetic field.
The magnetic field has both magnitude as well as direction.

 The S.I.Unit of magnetic field is Newton/Ampere-meter. It is also called Tesla and is denoted by T.
1T=1Newton1ampere x1meter 
So, 1T=1 N/Am

The magnetic field (B)of earth near its surface = 0.3 x 10-4T.

(i)The direction of magnetic field is indicated by the arrow in the line at any point (tangent).
(ii)The field lines come out of the north pole and emerge into the south pole(closed loops are formed).
(iii)No two field lines will never ever intersect each other.

Q11.State Right Hand Thumb Rule.
Answer: .Hold the wire carrying current in your hand, such that the thumb points in the direction of current, the direction of the curled fingers will indicate the the direction of magnetic field.



Q12.Define the phenomenon overloading.
Answer: .If the total current drawn by all the appliances at a particular time exeeds the bearing capacity of that wire, the wires of the domestic wiring get heated.This Phenomenon is called overloading.

Q.13. How can it be shown that magnetic field exist around a wire carrying current?
Answer: By using magnetic compass which, shows deflection.
A current-carrying straight conductor is placed in the east-west direction. What

Q.14 Will be the direction of the force experienced by this conductor due to earth’s magnetic field? How will this force get affected on? (a) reversing the direction of flow of current (b) doubling the magnitude of current. The direction of earth’s magnetic field is from G-south to G-north.
Answer: Let current is from west to east. Therefore force is vertically upwards.
(a) By reversing the direction of current, the direction of will be reversed i.e. vertically downwards.
(b) The magnitude of the force is doubled.

Q.15. A wire carrying current passes through the middle of the plane A perpendicular to it. If a magnetic needle is placed in the plane parallel to the wire. What will be the direction of the needle?
Answer: (i) along the tangent to a circle going anti-clockwise to an out coming current( to plane A).

Q.16.A wire carrying current passes through the middle of the plane A perpendicular to it. If a magnetic needle is placed in the plane perpendicular to the plane A, what will be the direction of the needle? Answer: .Any direction, as the needle is not influenced by a perpendicular field.

Q.17.If a magnetic needle is placed at the north pole in a horizontal plane, in what direction it will indicate? Why?
Answer: They will show random orientation as the magnetic field at the poles are along the vertical line and not on the horizontal plane.

Q.18.If a magnetic needle is placed at the north pole in a vertical plane, what will be its direction?
Answer: .They will stand vertically.

Q.19. Is a circular coil carrying current similar to magnet?
Answer: Yes

Q.20. What is the role of soft iron in the core of a solenoid?
Answer: It acts as an electromagnet.

Q.21. What are the factor on which the magnitude of the magnetic field (B) inside the solenoid depends on?

Answer: The magnitude of the magnetic field (B) inside the solenoid is:

(i). directly proportional to the to the current flowing through it.
            i.e.     B α I                           ①
(ii). directly proportional to the number of turns per unit length of the solenoid(n).
            i.e.      B  α n                         ②
       From ① and ②, we get
                B α nI
          Where n = N/l.
         Here, N = Total number of turns in the solenoid
          And   l = Length of solenoid.

Q. 22. What are the factor on which force acting on a current-carrying conductor placed in a magnetic field.

Answer: Magnitude of Force:- It has been found experimentally that the force (F) is:

(i). directly proportional to the current (I).

i.e. F∝ I ①

(ii). directly proportional to the length of the conductor inside the magnetic field.

i.e. F ∝ L ②

(iii). directly proportional to the magnitude of the magnetic field.

i.e. F α B ③

From ①, ② and ③, we get

F∝ ILB Or F=K x I x L xB

Q.23. What is magnetic flux?

Answer: The total number of lines of magnetic force in a material is called magnetic flux, f . The strength of the flux is determined by the number of magnetic domains that are aligned within a material. The total flux is simply the flux density applied over an area. Flux carries the unit of a weber, which is simply a tesla- meter2.

The number of magnetic lines of force cutting through a plane of a given area at a right angle is known as the magnetic flux density, B. The flux density or magnetic induction has the tesla as its unit. One tesla is equal to 1 Newton/(A/m). From these units, it can be seen that the flux density is a measure of the force applied to a particle by the magnetic field. The Gauss is the CGS unit for flux density and is commonly used by US industry. One gauss represents one line of flux passing through one square centimeter of air oriented 90 degrees to the flux flow.



To Download File visit JSUNILTUTORIAL

Magnetic effect of current class 10 Eduscore Questions with solution by cbse pathshala

Comments

CBSE ADDA :By Jsunil Sir : Your Ultimate Destination for CBSE Exam Preparation and Academic Insights

Class 10 Chapter 02 Acid Bases and Salts NCERT Activity Explanation

NCERT Activity Chapter 02 Acid Bases and Salt Class 10 Chemistry Activity 2.1 Indicator Acid Base Red litmus No Change Blue Blue Litmus Red No change Phenolphthalein Colourless Pink Methyl Orange Pink   Yellow Indictors are substance which change colour in acidic or basic media. Activity 2.2 There are some substances whose odour changes in in acidic or basic media. These are called olfactory indicators. Like onion vanilla, onion and clove. These changes smell in basic solution. Activity 2.3 Take about 5 mL of dilute sulphuric acid in a test tube and add few pieces of zinc granules to it. => You will observe bubbles of hydrogen gas on the surface of zinc granules. Zn + H2SO4 --> ZnSO4 + H2 => Pass the Hydrogen gas through the soap solution. Bubbles formed in the soap solution as Hydrogen gas it does not get dissolved in it

Living science ratna sagar class 6 solutions

Ratna sagar living science 6 answers by jsunil. Class6 Living science solution Term-1 Living Science Solution chapter-1 Source of food Download File Living Science Solution chapter-2 Component of food Download File Living Science Solution chapter-3 Fibre to fabric Download File Living Science Sol ch-4 Sorting of material into group Download File Living Science Soln ch-5 Separation of substance Download File Living Science Solution chapter-6 Change around Us Download File Living Science Solution ch-7 Living and Non Living Download File Living Science Solution ch-8 Getting to Know Plants Download File Living Science Sol ch-9 The Body and Its movements Download File Visit given link for full answer Class6 Living science solution Term-II

Class 10 Metal and Non MetalsChapter 03 NCERT Activity Solutions

X Class 10 NCERT Activity Explanation Class 10 Metals and Non Metals Activity 3.1 Page No. 37 Take samples of iron, copper, aluminium and magnesium. Note the appearance of each sample. They have a shining surface. Clean the surface of each sample by rubbing them with sand paper and note their appearance again. They become more shiny. => Freshly cut Metal have shiny surface Activity 3.2 Page No. 37 Take small pieces of iron, copper, aluminium, and magnesium. Try to cut these metals with a sharp knife and note your observations. They are very hard to cut. Hold a piece of sodium metal with a pair of tongs and try to cut it with a knife. Sodium can be cut easily with knife. Hence K and Na are soft metal cut with knife Activity 3.3 Page No. 38 Take pieces of iron, zinc, lead and copper try to strike it four or five times with a hammer. These metals are beaten into thin sheet on hammering. This property of metal is called malleability and metals are called malleable. Activity 3.4 Page

CBSE I NCERT 10th Numerical Problem solved Reflection and reflection of light

Q. 1. A concave mirror of focal length 20cm is placed 50 cm from a wall. How far from the wall an object be placed to form its real image on the wall?  Solution: V= -50 cm F= -20cm From mirror formula 1/u = 1/f – 1/v = -1/20+ 1/50 = - 3/100  U = - 33.3 cm Therefore, the distance of the object from the wall x =  50 – u X = 50 – 33.3 = 16.7 cm. Q.2. An object is placed at a distance of 40cm from a concave mirror of focal length 15cm. If the object is displaced through a distance of 20 cm towards the mirror, By how much distance is the image displaced? Answer: Here f = - 15 cm, u = - 40 cm Now 1/f = 1/u + 1/v Then 1/v = 1/f – 1/u Or V= uf/u-f =( - 40 x -15)/25 = -24 cm Then object is displaced towards the mirror let u1 be the distance object from the Mirror in its new position. Then u1 = -(40-20) = -20cm If the image is formed at a distance u1 from the mirror then v1 = u1f/u1-f = -20X-15/-20+15 = -60 cm. = - 20 x-15/-20+15 = -60 cm. Therefor

Electricity numerical for class 10 CBSE Trend Setter 50 Problems

1. The current passing through a room heater has been halved. What will happen to the heat produced by it? 2. An electric iron of resistance 20 ohm draws a current of 5 amperes. Calculate the heat produced in 30 seconds. 3. An electric heater of resistance 8 ohm takes a current of 15 A from the mains supply line. Calculate the rate at which heat is developed in the heater. 4. A resistance of 40 ohms and one of 60 ohms are arranged in series across 220 volt supply. Find the heat in joules produced by this combination in half a minute. 5. A resistance of 25 ohm is connected to a 12 V battery. Calculate the heat energy in joules generated per minute. 6. 100 joules of heat is produced per second in a 4 ohm resistor. What is the potential difference across the resistor? 7. An electric iron is connected to the mains power supply of 220 V. When the electric iron is adjusted at minimum heating’ it consumes a power of 360 W but at ‘maximum heating’ it takes a power of 840 W. Ca