Skip to main content

Who Discovered Ribosomes and How Did The Ribosome Gets Its Name

CBSE ADDA

Ribosomes are subcellular structures where protein synthesis occurs. Their primary function is to translate genes into proteins. They read the genetic instruction provided by the messenger RNA (mRNA) to assemble amino acids into long polypeptides (proteins). They are suspended in the cytosol, or attached in the rough endoplasmic reticulum (its rough appearance is due to the attached ribosomes) and in the nuclear envelope.
Ribosomes are made up of 35% proteins (also called ribonucleoproteins) and 65% RNA (also called ribosomal RNA) that forms a complex with each other. A ribosome measures 20 nanometer or 200 Angstroms; it is very small that a sophisticated microscope such as electron microscope is needed to view it. One ribosome is made up of two subunits that work together to synthesize protein using the genetic instruction in the messenger RNA.
Discovery of the Ribosome by George Palade with the Collaboration of Brilliant Scientists
The invention of the electron microscope has paved the way for the discovery of the ribosome. The Romanian cell biologist George Palade was the first to observe the ribosomes as dense particles or granule in the cytoplasm using the electron microscope in 1955. He published his discovery in the Journal of Biophysics, Biochemistry, and Cytology. (Take note that the term “ribosomes” came out later) Palade also refined the differential centrifugation procedure to isolate ribosomes from lysed cells t0 study them better.
With research collaboration with Philip Siekevitz, Palade found out the molecules attached to the rough endoplasmic reticulum are nothing but ribosomes. Further collaboration with other scientists led to the discovery of the function of ribosomes as the sites of protein synthesis.
Palade has focused his career to the study of the structure and functions of ribosomes. His contribution to the study of ribosomes was recognized when he shared the Nobel Prize for Physiology and Medicine with his co-researchers in 1974. In addition to the Nobel Prize, Palade also received numerous recognitions from different scientific societies, foundations, and universities during his lifetime.
How Did The Ribosome Gets Its Name
The term “ribosome” was proposed by scientist Richard B. Roberts during a scientific symposium on microsomal particles and protein synthesis in 1958. The term has arisen when there was disagreement among scientists in the symposium on how to call or designate the subcellular structure (the ribosome). Scientists at the symposium accepted the term because it is satisfactory and sounds good. Since then, the term “ribosome” was widely used to describe the subcellular structure involved in proteinsynthesis.


Comments

CBSE ADDA :By Jsunil Sir : Your Ultimate Destination for CBSE Exam Preparation and Academic Insights

Class 10 Chapter 02 Acid Bases and Salts NCERT Activity Explanation

NCERT Activity Chapter 02 Acid Bases and Salt Class 10 Chemistry Activity 2.1 Indicator Acid Base Red litmus No Change Blue Blue Litmus Red No change Phenolphthalein Colourless Pink Methyl Orange Pink   Yellow Indictors are substance which change colour in acidic or basic media. Activity 2.2 There are some substances whose odour changes in in acidic or basic media. These are called olfactory indicators. Like onion vanilla, onion and clove. These changes smell in basic solution. Activity 2.3 Take about 5 mL of dilute sulphuric acid in a test tube and add few pieces of zinc granules to it. => You will observe bubbles of hydrogen gas on the surface of zinc granules. Zn + H2SO4 --> ZnSO4 + H2 => Pass the Hydrogen gas through the soap solution. Bubbles formed in the soap solution as Hydrogen gas it does not get dissolved in it

Living science ratna sagar class 6 solutions

Ratna sagar living science 6 answers by jsunil. Class6 Living science solution Term-1 Living Science Solution chapter-1 Source of food Download File Living Science Solution chapter-2 Component of food Download File Living Science Solution chapter-3 Fibre to fabric Download File Living Science Sol ch-4 Sorting of material into group Download File Living Science Soln ch-5 Separation of substance Download File Living Science Solution chapter-6 Change around Us Download File Living Science Solution ch-7 Living and Non Living Download File Living Science Solution ch-8 Getting to Know Plants Download File Living Science Sol ch-9 The Body and Its movements Download File Visit given link for full answer Class6 Living science solution Term-II

Class 10 Metal and Non MetalsChapter 03 NCERT Activity Solutions

X Class 10 NCERT Activity Explanation Class 10 Metals and Non Metals Activity 3.1 Page No. 37 Take samples of iron, copper, aluminium and magnesium. Note the appearance of each sample. They have a shining surface. Clean the surface of each sample by rubbing them with sand paper and note their appearance again. They become more shiny. => Freshly cut Metal have shiny surface Activity 3.2 Page No. 37 Take small pieces of iron, copper, aluminium, and magnesium. Try to cut these metals with a sharp knife and note your observations. They are very hard to cut. Hold a piece of sodium metal with a pair of tongs and try to cut it with a knife. Sodium can be cut easily with knife. Hence K and Na are soft metal cut with knife Activity 3.3 Page No. 38 Take pieces of iron, zinc, lead and copper try to strike it four or five times with a hammer. These metals are beaten into thin sheet on hammering. This property of metal is called malleability and metals are called malleable. Activity 3.4 Page

CBSE I NCERT 10th Numerical Problem solved Reflection and reflection of light

Q. 1. A concave mirror of focal length 20cm is placed 50 cm from a wall. How far from the wall an object be placed to form its real image on the wall?  Solution: V= -50 cm F= -20cm From mirror formula 1/u = 1/f – 1/v = -1/20+ 1/50 = - 3/100  U = - 33.3 cm Therefore, the distance of the object from the wall x =  50 – u X = 50 – 33.3 = 16.7 cm. Q.2. An object is placed at a distance of 40cm from a concave mirror of focal length 15cm. If the object is displaced through a distance of 20 cm towards the mirror, By how much distance is the image displaced? Answer: Here f = - 15 cm, u = - 40 cm Now 1/f = 1/u + 1/v Then 1/v = 1/f – 1/u Or V= uf/u-f =( - 40 x -15)/25 = -24 cm Then object is displaced towards the mirror let u1 be the distance object from the Mirror in its new position. Then u1 = -(40-20) = -20cm If the image is formed at a distance u1 from the mirror then v1 = u1f/u1-f = -20X-15/-20+15 = -60 cm. = - 20 x-15/-20+15 = -60 cm. Therefor

Electricity numerical for class 10 CBSE Trend Setter 50 Problems

1. The current passing through a room heater has been halved. What will happen to the heat produced by it? 2. An electric iron of resistance 20 ohm draws a current of 5 amperes. Calculate the heat produced in 30 seconds. 3. An electric heater of resistance 8 ohm takes a current of 15 A from the mains supply line. Calculate the rate at which heat is developed in the heater. 4. A resistance of 40 ohms and one of 60 ohms are arranged in series across 220 volt supply. Find the heat in joules produced by this combination in half a minute. 5. A resistance of 25 ohm is connected to a 12 V battery. Calculate the heat energy in joules generated per minute. 6. 100 joules of heat is produced per second in a 4 ohm resistor. What is the potential difference across the resistor? 7. An electric iron is connected to the mains power supply of 220 V. When the electric iron is adjusted at minimum heating’ it consumes a power of 360 W but at ‘maximum heating’ it takes a power of 840 W. Ca